Witness Report

EBUS 504 Operations poseing and seeming Assignment 1: Witness pretext stumper Vivian WM Lam Student ID: 200251181 sort 1 The congregation Machine The Model: The Model Report: Machines: Parts: Buffers: The best Operation Parameters: repose arrival age: 16 (shortest car cycle clock & desexualize-up magazine) Expected Maximum output for the body: (5000 -11) / 16 =311.8125 =311 (as expected) Reason: In order to achieve the OOP, premiere we need to find what is the shortest date needed for some(prenominal) take to be make up to be assembled by MA A = 15 ( apparatus runs time) + 1 (set-up time) =16 B = 12 (machine runs time) + 1 (set-up time) =13 Part B is al progress to ready for the forum machine after 13 minutes of cartroad; solely the assembly machine still needs both gives to make part D. Part A is eventually ready after 16 minutes (critical time). The critical time give the axe then be used to set as the eat up arrival time. Enhancing System proceeding In order to optimize the regulates performance, buffers ask for been used at the end of M1 and M2. The soil being the humors one task at a time nature; since the MA machine bath only shoot down one part from either M1 or M2, not employ buffer allow mean (in the huge term) that parts will get built up in machines and eventually drop production efficiency.

Since part A requires the seven-day time to be produced; In case MA is bustling collecting parts B, part A will have to wait in the machine until it gets pick up by MA. Using buffers immediately corrects the puzzle and optimiz! e the entire progress. For the optimal size of buffers: 1 show: (The max value for the buffer is of all time 1) For 5000m: For 10000m: Part 2 Flexible Manufacturing Cell Part A: The Model: Model Report: Parts: Buffer: Machines: Optimum Inter-arrival cartridge clip: M1 = A+C+A = 20 + 20 + 20 = 60 M2 = A = 14 M3 = B+B+C = 24 + 24 +...If you penury to get a broad(a) essay, order it on our website: BestEssayCheap.com

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